9(a+3)=10[a-(5-a)]

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Solution for 9(a+3)=10[a-(5-a)] equation:


Simplifying
9(a + 3) = 10[a + -1(5 + -1a)]

Reorder the terms:
9(3 + a) = 10[a + -1(5 + -1a)]
(3 * 9 + a * 9) = 10[a + -1(5 + -1a)]
(27 + 9a) = 10[a + -1(5 + -1a)]
27 + 9a = 10[a + (5 * -1 + -1a * -1)]
27 + 9a = 10[a + (-5 + 1a)]

Reorder the terms:
27 + 9a = 10[-5 + a + 1a]

Combine like terms: a + 1a = 2a
27 + 9a = 10[-5 + 2a]
27 + 9a = [-5 * 10 + 2a * 10]
27 + 9a = [-50 + 20a]

Solving
27 + 9a = -50 + 20a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-20a' to each side of the equation.
27 + 9a + -20a = -50 + 20a + -20a

Combine like terms: 9a + -20a = -11a
27 + -11a = -50 + 20a + -20a

Combine like terms: 20a + -20a = 0
27 + -11a = -50 + 0
27 + -11a = -50

Add '-27' to each side of the equation.
27 + -27 + -11a = -50 + -27

Combine like terms: 27 + -27 = 0
0 + -11a = -50 + -27
-11a = -50 + -27

Combine like terms: -50 + -27 = -77
-11a = -77

Divide each side by '-11'.
a = 7

Simplifying
a = 7

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